utilium
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    Type Alias Remove<A, B>

    Remove: Empty extends B ? A : Remove<Shift<A>, Shift<B>>

    Extracts from A what is not B

    Type Parameters

    • A extends unknown[]
    • B extends unknown[]

    It does not remove duplicates (so Remove<[0, 0, 0], [0, 0]> yields [0]). This is intended and necessary behavior.

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